Question

So I need to know what is the probability that a randomly selected club member reads about 1 hour per week and prefers any paperback books?

Answer 1

First, find the total number of people that were surveyed,

`T=6+3+2+6=17`

Then, look for the cell in the table that corresponds to the intersection between 'Paperback books' and 'About 1 hour per week'. The number in such cell is 3; therefore, the probability we are looking for is

`P(Paperback\cap1hour)=(3)/(T)=(3)/(17)`

The answer is 3/17.