Question

How does finding the square root of a number compare to finding the cube root of a number. Use the number 64 in your explanation.

Can someone please help me with this?

Answer 1

if
`x^2=y` , then
`\sqrt[2]{y}=\sqrt[2]{x^2}=x`

if
`x^3=y` , then
`\sqrt[3]{y}=\sqrt[3]{x^3}=x`


ok

`64=8^2=4^3`

so

`\sqrt[2]{64}=\sqrt[2]{8^2}=8`

`\sqrt[3]{64}=\sqrt[3]{4^3}=4`

well, the cube root usually bigger