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What was Helen's nine week grade in marine biology round to 2 decimal places

User Peter Marshall
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1 Answer

30 votes
30 votes

From the question, the test scores were 85, 57 and 82,

To find the 55% average test score below,


\begin{gathered} Av\text{ test score=}(85+57+82)/(3)=(224)/(3) \\ 55\text{\% of }(224)/(3)=(55)/(100)*(224)/(3)=(616)/(15)=41.067 \end{gathered}

The daily scores were 75, 86, 98, 97, 65, 79 and 85,

To find the 20% average daily score,


\begin{gathered} Av\text{ daily score=}\frac{75+86+98+97+65+79+85_{}}{7}=(585)/(7) \\ 20\text{\% of }(585)/(7)=(20)/(100)*(585)/(7)=16.714 \end{gathered}

The group presentation scores were 86, 87, 65 and 91

To find the 25% average group presentation score,


\begin{gathered} Av\text{ group presentation=}(86+87+65+91)/(4)=(329)/(4) \\ 25\text{\% of }(329)/(4)=(25)/(100)*(329)/(4)=20.563 \end{gathered}

Helen's nine weeks score/grade will be,


=41.067+16.714+20.563=78.344=78.34\text{ (2 d.p)}

Answer is 78.34 (2 decimal places)

User Whereisleo
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