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Indicate the equation of the given line in standard form.

The line through (2, -1) and parallel to a line with slope of 3/4

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Since the slope stays the same as it's parallel, we have y=(3/4)x+b. Plugging (2,-1) in, we get -1=3*2/4+b=6/4+b=1.5+b. Subtracting 1.5 from both sides, we get -2.5=b and our equation being y=(3/4)x-2.5 (since in y=mx+b, y and x remain as variables)
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