If y varies directly as x and x = 12 when y = 24, what is x when y = 8.?
So, y = c * x
where c is constant
x = 12 when y = 24
so,
24 = c * 12
c = 24/12 = 2
so,
y = 2x
Now, need to find x when y = 8
so,
8 = 2x
x = 8/2 = 4
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From the graph:
y-intercept = 3 , it is the value of y when x = 0
the general form of the line: y = mx + b
where b is y-intercept
So, y = mx + 3
to find m, choose point like (2 , 2) and substitute with it
so, y = 2 when x =2
2 = 2m + 3
2m = -1
m = -1/2 = -0.5
so, y = -0.5x + 3
so, to find x-intercept is the value of x when y = 0
so, 0 = -0.5x + 3
0.5x = 3
x = 3/0.5 = 6
m is the slope = -0.5
b is y-intrcept = 3