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The sum of a number and 20 is no more than the sum of the square of the number and 9

User Ali Mezal
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1 Answer

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Translate the given statement into an inequality:

x+20 is less than or equal to x^2+9. Solve for x.

Subtract x+20 from both sides of this inequality. We get 0 is less than or equal to x^2+9-x-20, or

0 is less than or equal to x^2-x-11

Temporarily set x^2-x-11 = to 0 and solve for x:

Using the quadratic formula with a=1, b=-1 and c=-11,

-(-1) plus or minus sqrt([-1]^2-4(1)(-11))
x=---------------------------------------------------------
2(1)
1 plus or minus sqrt(45)
= ------------------------------------
2
1 plus or minus 3sqrt(5)
= ------------------------------------
2

Evaluate these two results and plot them on a number line. Based upon these results (values), write inequalities to represent the distinct intervals:

(-infinity,a), (a,b), (b, infinity

Determine which interval or intervals contain x values that make the given inequality true.
User Palmin
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