Question

Consider the reaction of magnesium metal with hydrochloric acid to produce magnesium chloride and hydrogen gas. if 3.38 mol of magnesium and 3.38 mol of hydrochloric acid are reacted, how many grams of magnesium chloride are produced?

Answer 1

Mg + 2HCl --> MgCl2 + H2

From the balanced equation , 2 moles of HCl produces 1 mole MgCl2
Therefore 3.38 moles of Hcl will produce
1/2 × 3.38 = 1.69
Mass = Moles × Mr of MgCl2
= 1.69 × ( 24 + ( 35.5 x 2) )
= 1.69 x 95
= 160.55 g

Answer 2

Answer: The mass of magnesium chloride produced in the given reaction is 16.09 grams.

Step-by-step explanation:

We are given:

Moles of magnesium = 3.38 mol

Moles of hydrochloric acid = 3.38 mol

The chemical equation for the reaction of magnesium and hydrochloric acid follows:

`Mg+2HCl\rightarrow MgCl_2+H_2`

By Stoichiometry of the reaction:

2 moles of hydrochloric acid reacts with 1 mole of magnesium.

So, 3.38 moles of hydrochloric acid will react with =
`(1)/(2)* 3.38=1.69mol` of magnesium.

As, given amount of magnesium is more than the required amount. So, it is considered as an excess reagent.

Thus, hydrochloric acid is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of hydrochloric acid is producing 1 mole of magnesium chloride.

So, 3.38 moles of hydrochloric acid will react with =
`(1)/(2)* 3.38=0.169moles` of magnesium chloride.

Now, calculating the mass of magnesium chloride by using equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}`

Molar mass of magnesium chloride = 95.21 g/mol

Moles of magnesium chloride = 0.169 moles

Putting values in above equation, we get:

`0.169mol=\frac{\text{Mass of magnesium chloride}}{95.21g/mol}\\\\\text{Mass of magnesium chloride}=16.09g`

Hence, the mass of magnesium chloride produced in the given reaction is 16.09 grams.