Question

What is the change in energy if the electron from part a now drops to the ground state?what is the wavelength λ of the photon that has been released in part b?

Answer 1

The change in energy when the electron drops to the ground state can be calculated. The wavelength of the released photon can be determined using the equation: wavelength = hc / energy.

Step-by-step explanation:

When an electron drops from a higher energy level to the ground state, it releases energy in the form of a photon. The change in energy can be calculated by taking the difference between the initial energy and the energy of the ground state. The wavelength of the photon can be determined using the equation:

wavelength = hc / energy

where h is Planck's constant (6.626 x 10^-34 J s), c is the speed of light (3.00 x 10^8 m/s), and energy is the change in energy calculated earlier.

Answer 2

Change in energy: ΔE = E1 - E4


E1 = -13.6 eV(1.602 x 10^-19 J/eV)/1^2 = -2.18 x 10^-18 J


ΔE = -2.18 x 10^-18 J - (-1.36 x 10^-19 J) = -2.04 x 10^-18 J



Wavelength of the photon: E = hν = hc/λ, where h = Planck's constant and v = frequency in s^-1; λ = wavelength in m, and c = 3.00 x 10^8 m/s


2.04 x 10^-18 J = (6.626 x 10^-34 J*s)(3.00 x 10^8 m/s)/λ


λ = (6.626 x 10^-34 J*s)(3.00 x 10^8 m/s)/(2.04 x 10^-18 J) = 9.74 x 10^-8 m