Question

Find a point e on cd such that the ratio of ce to cd is 3/8

Answer 1

The answer is -3 I took the test and I put a different answer that this cite told me to use and it was wrong

Answer 2

`x = \displaystyle(3x_2 + 5x_1)/(8), y = \displaystyle(3y_2 + 5y_1)/(8)`

Explanation:

We are given the following information:

The point E on CD such that the ratio of CE to CD is 3:8.

Thus E divides CD into ratio 3:5.

Let
`(x_1,y_1)` be the coordinate of C and
`(x_2,y_2)` be the coordinates of D.

Section formula:

Let (x,y) be the coordinates of E, then,

`x = \displaystyle(mx_2 + nx_1)/(m+n), y = \displaystyle(my_2 + ny_1)/(m+n)`,

where m:n is the ration where point E divides CD into.

Here, m:n = 3:5

Putting these values, we get,

`x = \displaystyle(3x_2 + 5x_1)/(8), y = \displaystyle(3y_2 + 5y_1)/(8)`