Given:
Total No. of students in the travel club = 61
Students visited Country A = 21
Students visited Country B = 29
Students visited Country C = 25
Students visited Country A and B = 8
Students visited Country C only = 14
Students visited Country A only = 11
No. of members who have not been to any country = No. of members who have been to all 3 countries ( *let's call the two of them x since they are equal)
Required:
a. No. of students whho have been to all 3 countries
b. No. of studens who have been to Country B only
Solution:
Total Number of Students = A + B + C - AB - AC -BC + ABC + NONE
61 = 21 + 29 + 25 - 8 - AC - BC + X + X
61 = 67 - AC - BC + 2X
AC + BC = 67 - 61 + 2X
AC + BC = 6 + 2X
Only in Country A = A - AB - AC + ABC
11 = 21 - 8 - AC + X
11 = 13 - AC + X
AC = 13 -11 + X
AC = 2 + X
Only in Country C = C - AC - BC + X ( but, AC = 2 + X )
14 = 25 - ( 2 + X ) - BC + X
14 = 25 - 2 - X - BC + X
BC = 25 - 2 -14 -X + X
BC = 9
Only in Country B = B - AB - BC + ABC
Only in Country B = 29 - 8 - 9 + X
Only in Country B = 12+ X
Also, we know that AC + BC = 6 + 2X ( but, AC = 2 + X and BC = 9 )
Thus,
AC + BC = 6 + 2X
( 2 + X ) + 9 = 6 + 2X
2 + X + 9 = 6 + 2X
11 + X = 6 + 2X
11 - 6 = 2X - X
5 = X
If X = 5 then,
Only in Country B = 12+ X = 12 + 5 = 17
and AC = 2 + X = 2 + 5 = 7
Answer:
a. No. of students whho have been to all 3 countries = 5
b. No. of studens who have been to Country B only = 17