Question

36x² + 49y² = 1,764 the foci are located at:

Answer 1

Given:

`36x^2+49y^2=1764`
`(36x^2)/(1764)+(49y^2)/(1764)=(1764)/(1764)`
`(x^2)/(49)+(y^2)/(36)=1`
`(x^2)/(7^2)+(y^2)/(6^2)=1`
`a^2=49;b^2=36`
`c^2=a^2-b^2`
`c^2=49-36`
`c^2=13`
`c=\pm\sqrt[]{13}`
`(-\sqrt[]{13},0)\text{ \& (}\sqrt[]{13},0)\text{ are the focii of the given ellipse.}`