Question

How much water should be added to 1 gallon of pure antifreeze to obtain a solution that is 35% antifreeze?

To obtain a 35% antifreeze solution, □ gallon(s) of water should be added
(Simplify your answer.)

Answer 1

Assume that x gallon water is added: 35% antifreeze
= 1 / (x + 1) = 0.35
1 = 0.35 x + 0.35
0.65 = 0.35(x)
x = 1.857 gallons
The answer is 1.89 gallons of waters should be added to 1 pure antifreeze to obtain a solution that is 35% antifreeze.

Answer 2

Answer: 1.9 gallon

Explanation:

Let 'x' be the amount of water that needed to be added to 1 gallon of pure antifreeze to obtain a solution that is 35% antifreeze.

Total mass of solution = 1+x

Ratio of amount of antifreeze to the total solution :
`(1)/(1+x)`

Ratio of value of antifreeze to the total solution :
`(0.35)/(1)`

The proportion of the amount of antifreeze to the total solution will be :

`(1)/(1+x)=(0.35)/(1)\\\\\Rightarrow\ 1+x=(1)/(0.35)=1.85714285714\approx2.9\\\\\Rightarrow\ x=2.9-1=1.9`

Hence, the amount of water that is needed to be added =1.9 gallon