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Find the equation of the line passing through point (2,5) and parallel to y = -1/2x -2

Find the equation of the line passing through point (2,5) and parallel to y = -1/2x-example-1
User Rami Awar
by
2.7k points

1 Answer

20 votes
20 votes

SOLUTION

We are told to find the equation of the line passing through the points (2, 5) and parallel to


y=-(1)/(2)x-2

Now, equation of line in slope intercept form is given as


y=mx+b

comparing this to


y=-(1)/(2)x-2

We can see that m for that equation is


-(1)/(2)

m is the slope.

For two parallel lines, m1 = m2. That is their slopes are equal.

So we will use our m as


m=-(1)/(2)

For equation of line for point and slope form, we have the formula as


y-y_1=m(x-x_1)

using this, the equation of the line becomes


\begin{gathered} y-y_1=m(x-x_1) \\ \\ y-5_{}=-(1)/(2)(x-2) \\ \\ y-5=-(x)/(2)+(2)/(2) \\ \\ y-5=-(x)/(2)+1 \\ \\ y=-(x)/(2)+6 \\ \\ y=-(1)/(2)x+6 \end{gathered}

Therefore, option C is the correct answer

User Flixer
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3.4k points