Question

24. Two boys were each pushing a box to the right, one boy applied a force of 3N and

the other boy applied a force of 5N. Another boy was pushing the box to the left
with a force of 8N. What was the net force of the box?

Answer 1

Step-by-step explanation:

Two boys were each pushing a box to the right, one boy applied a force of 3N and the other boy applied a force of 5N.

Total force applied to the left = 3 + 5 = 8 N . The forces are added up because they act in the same direction .

Another boy was pushing the box to the left with a force of 8N.

8 N force acts opposite to the total force of 8 N exerted by two earlier boys so

net force = 8N - 8N = 0 .

Net force on the box = 0 .