Question

A parabola y=1/2x^2-4x+21 can you help me find the vertex form of this parabola please and thank you :)

Answer 1

Ok
First factor out the first 2 terms as follows:-

y = 1/2(x^2 - 8x) + 21

Now complete the square on x^2 - 8x:-

y = 1/2[ (x - 4)^2 - 16] + 21

y = 1/2(x - 4)^2 - 8 + 21

y = 1/2(x - 4)^2 + 13 Answer