Question

Please can someone help me

There are three students in Mrs. Reed class that have consecutive ages. The sum of their ages is 45. Write the equation that would model how to solve this problem.


A. n+n+2+n+2=45
B. n+n+1+n+3=45
C. n+n+2+n+4=45
D. n+n+1+n+2=45


update: answer is D

Answer 1

he said its d he's right

Explanation:

Answer 2

if the answer is D. the equation to represent the ages of students is:
n + n+1 + n+2 = 45
it is showing that n is the age of one student and the other student has age one year more than the first one and third students has age of 2 years more than first student and one year greater than the second student. if we solve this equation for the value of n, we get;
3n + 3 = 45
3n = 45 -3
3n = 42
n = 14
so the age of one student is 14, second student 15 and third student 16 years.
and if we add there ages, 14 + 15 + 16 = 45