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How many solutions does the equation have? 4(z−5)+2=4z−18
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4 votes
How many solutions does the equation have?

4(z−5)+2=4z−18

User Igor Martins
by
8.9k points

2 Answers

1 vote
All real numbers is the solution of this equation

4z - 20 +2 = 4z - 18

4z - 18 = 4z - 18
+18 +18

4z = 4z


User Chloraphil
by
8.4k points
6 votes
Distribute the 4:
4z - 20 + 2 = 4z - 18
Subtract 4z
-20 + 2 = -18
-18 = -18
This is true so that means there are infinite number of solutions... z could be anything!
User Moira
by
7.9k points
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