Question

A pitcher throws a softball toward home plate. When the ball hits the catcher’s mitt, its horizontal velocity is 32 meters/second. The softball’s velocity goes to 0 meters/second in 0.8 seconds when caught. If the softball has a mass of 0.2 kilograms, what’s the force of the impact? Use F = ma, where .

Answer 1

8 Newtons.

Step-by-step explanation:

Answer 2

Answer: The force of the impact is 8.0 Newtons

Step-by-step explanation:

Given

`Initial\: velocity(V_i)= 32.0\, (m)/(s) ,Final\, velocity ( V_f)=0 (m)/(s),Time(t)=0.8 seconds`

Using equation of motion

`V_f=V_i+at` where a= acceleration of softball

=>
`0=32+a* 0.8=>a= -40\, (m)/(s^(2))`

Thus magnitude of the force of the impact is

`F=\left | ma \right |=>F=0.2* 40\; Newtons=8.0\: Newtons`

Thus the force of the impact is 8.0 Newtons