Question

A + 7.22 nC point charge and a - 2.6 nC point charge are 4.46 cm apart. What is the electric field strength at the midpoint between the two charges?

Answer 1

Given

Charge is

`q_1=7.22\text{ nC}`

The second charge is

`q_2=-2.6\text{ nC}`

The distance between the charges,

`r=4.46\text{ cm=4.46}*10^(-2)m`

To find

The electric field strength

Step-by-step explanation

The electric field strength is given by

`F=k(q_1q_2)/(r^2)`

Putting the values,

`\begin{gathered} F=9*10^9(7.22*10^(-9)*2.6*10^(-9))/((4.46*10^(-2))^2) \\ \Rightarrow F=8.49*10^(-5)N \end{gathered}`

Conclusion

The electric field strength is

`8.49*10^(-5)N`