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If the average of 12 consecutive odd integers is 328, what is the least of these integers

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x+1+x+2+x+3+x+4+x+5+x+6+x+7+x+8+x+9+x+10+x+11+x+12/12
12x+78/12 = 132 times 12 is
12x+78 = 1,548 minus 78
12x = 1,506 divide by 12
x = 125.5 I believe is the answer, sorry if it is wrong



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