Question

How many chloride ions are present in 0.100 mol of MgCl2

Answer 1

To identify the amount of chloride ions present in 0.1 mol of MgCl2, first know the amount of mols of Chloride. The answer is 0.2 mol since you just need to multiply 0.1 to 2 because there are 2 chloride in the compound. Then, multiply the mols to 6.02x10^23. The answer would be 1.204x10^23 chloride ions.

Answer 2

Answer : The number of chloride ions present in 0.100 mole of
`MgCl_2` are,
`1.2044* 10^(23)`

Explanation : Given,

Moles of
`MgCl_2` = 0.100 mole

As we know that, 1 mole contains
`6.022* 10^(23)` number of ions.

In
`MgCl_2`, there are one magnesium ion and two chloride ions.

As, 1 mole
`MgCl_2` contains
`2* (6.022* 10^(23))` number of chloride ions.

So, 0.100 mole
`MgCl_2` contains
`0.100* 2* (6.022* 10^(23))=1.2044* 10^(23)` number of chloride ions.

Therefore, the number of chloride ions present in 0.100 mole of
`MgCl_2` are,
`1.2044* 10^(23)`