Question

1. Put 9y=-3x-39 into standard form

2. Put -2x+2y=-2 into standard form
3. Solve the system by either using substitution or elimination{-2x=20,
3x-4y=-2}
4.

Answer 1

1. Put 9y=-3x-39 into standard form
3x + 9y = -39 ...this is standard form

2. Put -2x+2y=-2 into standard form
2x - 2y = 2 ...this is standard form

3. Solve the system by either using substitution or elimination
{-2x=20, 3x-4y=-2}

-2x = 20
x = -10

substitute x = -10 into 3x-4y=-2

3x-4y=-2
3(-10)-4y=-2
-30 - 4y = -2
4y = -28
y = -7

answer
x = -10 and y = -7

Answer 2

1. 9y = -3x - 39....add 3x to both sides
3x + 9y = -39 <== standard form

2. -2x + 2y = -2. ..multiply by -1
2x - 2y = 2 <== standard form

3. -2x = 20
x = -20/2
x = -10....now sub this back into the second equation

3x - 4y = -2
3(-10) - 4y = -2
-30 - 4y = -2
-4y = -2 + 30
-4y = 28
y = -28/4
y = -7

solution is (-10,-7) <== solution