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The highest barrier that a projectile can clear is 24.7 m, when the projectile is launched at an angle of 23.0 ° above the horizontal. what is the projectile's launch speed?

1 Answer

4 votes
Initial velicity Vo.

Sin(23) = 24.7 / Vo
Vo = 24.7/Sin(23)
V0 = 63.2 m/sec
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