Question

The highest barrier that a projectile can clear is 24.7 m, when the projectile is launched at an angle of 23.0 ° above the horizontal. what is the projectile's launch speed?

Answer 1

Initial velicity Vo.

Sin(23) = 24.7 / Vo
Vo = 24.7/Sin(23)
V0 = 63.2 m/sec