Question

A rolling ball has an initial velocity of 1.6 meters per second. if the ball has a constant acceleration of 0.33 meters per second squared in the same direction as its movement, what is its velocity after 3.6 seconds?

Answer 1

We have:

Initial velocity (u) = 1.6 m/s
Constant acceleration (a) = 0.33 m/s²
Time (t) = 3.6 sec

There are five constant acceleration equations that would help us to find the velocity:


`v=u+at`

`s=ut+ (1)/(2)at^2`

`s= (1)/(2)(u+v)t`

`v^2=u^2+2as`

`s=vt- (1)/(2)at^2`

Since we have
`u, a, t` and we want
`v`
We will use the first formula
`v=u+at`


`v=1.6+(0.33)(3.6)`

`v= 2.788` m/s