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What is the bicyclist's velocity at t=35s?

User Suroj
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2 Answers

2 votes

Final answer:

The bicyclist's velocity at t = 35s, calculated from the velocity function v(t) = (10 – 4t)m/s, is -130 m/s. This indicates the direction is opposite to the defined positive direction, but the value suggests a typo in the given information.

Step-by-step explanation:

Given the velocity function for the bicyclist, v(t) = (10 – 4t) m/s, we can calculate the bicyclist's velocity at t = 35s. To do this, we simply plug 35 into the function:

v(35) = 10 - 4(35) = 10 - 140 = -130 m/s.

The negative sign indicates that the direction of the bicyclist's velocity is opposite to the direction defined as positive in the problem. However, this answer seems physically unreasonable for a bicyclist and might be due to a typographical error in the original velocity function or in the statement of time given as t = 35s, as typical bicycle speeds are much lower. If there was a mistake and the time given should have been less, within a typical bicyclist's range, you'd need to correct the function accordingly. Nevertheless, with the given function and time, velocity is mathematically -130 m/s.

User Antony Koch
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8.1k points
5 votes
Since we are talking about the relation between the velocity and the time, the distance must be given.
Since no distance is given here, then I'll just tell you how to solve this question in terms of equations and you can substitute with the numbers you have.

The velocity can be calculated using the following rule:
velocity = distance / time
we are given the time as 3.5 seconds, therefore:
velocity = distance / 3.5
User Ashish Rajan
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