Question

A car traveling at 32 m/s starts to decelerate steadily. It comes to a complete stop in 14 seconds. What is its acceleration?

Answer 1

Hello!

A car traveling at 32 m/s starts to decelerate steadily. It comes to a complete stop in 14 seconds. What is its acceleration?

We have the following data:

Vi (initial velocity) = 32 m/s (starts)

Vf (final velocity) = 0 m/s (stop)

t (time) = 14 s

a (acceleration) = ? (in m/s²)

We apply the data to the formula of the hourly function of the velocity, let us see:

`V_f = V_i + a*t`

`0 = 32 + a*14`

`- 32 = 14\:a`

`14\:a = - 32`

`a = (-32)/(14)`

`\boxed{\boxed{a = - 2.28\:m/s^2}}\Longrightarrow(the\:car\:slows\:down)\:\:\:\:\:\:\bf\green{\checkmark}`

Answer:

The acceleration is -2.28 m/s² (decelerate)

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`\bf\red{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}`

Answer 2

We have:

Initial velocity (u) = 32 m/s
Final velocity (v) = 0 m/s ⇒ The value is zero because the car comes to stationary position when it stops
Time = 14 seconds

We can use one of the constant acceleration equation:

`v=u+at` where
`a` is the acceleration


`0=32+14a`

`32=-14a`

`a=- (32)/(14)=-2.3m/s^(-2)`

The acceleration is 2.3 m/s⁻² and the negative sign shows deceleration