Question

A chemist needs to find out how large of a container would be required to contain the products of an ammonia decomposition. If 8.91 mol H2 are produced during the reaction, how many moles of N2 are produced?

Answer 1

the answer is 2.97 mol N2

Answer 2

Answer : The moles of
`N_2` produced are, 2.97 moles

Solution : Given,

Moles of
`H_2` = 8.91 moles

The balanced decomposition reaction of ammonia will be,

`NH_3\rightarrow 3H_2+N_2`

From the balanced reaction, we conclude that

When 2 moles of
`NH_3` decomposes to produce 3 moles of
`H_2` and 1 mole of
`N_2`

If the moles of
`H_2` is 3 moles then the moles of
`N_2` produces = 1 mole

If the moles of
`H_2` is 8.91 moles then the moles of
`N_2` produces =
`(8.91moles)/(3moles)=2.97moles`

Therefore, the moles of
`N_2` produced are, 2.97 moles