Question

Evaluate √7x(√x−7√7) please Show your Work thanks.

Answer 1

remember

`(√(a))(√(b))=√(ab)`


first distribute


`√(7x^2)-7√(49x)=`

`(√(x^2))(√(7))-7(√(49))(√(x))=`

`x√(7)-7(7)√(x)=`

`x√(7)-49√(x)` is simlified form
to evaluate, we would need a value for x

Answer 2

expand by multiplying √7x⋅√x and √7x⋅7√7

√7x(√x−7√7)=√7x⋅√x−√7x⋅7√7

You can make√7x into √7⋅√x

=√7⋅√x⋅√x−√7⋅√x⋅7⋅√7=√7⋅(√x)2−(√7)2⋅√x⋅7

since squaring and square roots are opposite, they cancel

=√7⋅x−7⋅√x⋅7=x√7−49√x
I hope the square root symbols worked. I had to copy and paste from word. Hopefully this is what you needed!