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How many solutions does the equation have? 4(z−5)+2=4z−18 0 1 infinitely many
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1 vote
How many solutions does the equation have?

4(z−5)+2=4z−18

0

1

infinitely many

User RajV
by
8.3k points

2 Answers

3 votes

Answer:

The correct answer would be infinitely many

this is true because the factor of z could be anything

Explanation:


User Shixiang Wang
by
8.0k points
5 votes
infinitely many, hope that helped
User Tudor Morar
by
8.3k points
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