2NaOH(aq) + H2SO4(aq) --> Na2SO4(aq) +2H20(I)
To solve this problem we use this formula:
M1 x V1 = M2 x V2 (1)
1 is for the acid and 2 is for the base.
M1 = 0.361 M sulfuric acid
V1 = unknown
M2 = 0.436 M sodium hydroxide
V2 = 46.96 mL
We clear V1 from (1) ==> V1 = M2 x V2/M1
===> V1 = 0.436 M x 46.96 mL/0.361 M = 56.72 mL
Answer: V1 = 56.72 mL H2SO4