Question

Express the diameter of a ground-state hydrogen atom in meters using a power of 10.

Answer 1

The diameter of a ground-state hydrogen atom is approximately 1.0584 × 10-10 meters, which can be rounded to an order of magnitude of 10-10 meters.

Step-by-step explanation:

The diameter of a ground-state hydrogen atom can be expressed in meters using a power of 10. The ground state of a hydrogen atom is described by the Bohr model which establishes that the radius of the orbit in which the electron moves is known as the Bohr radius. The Bohr radius (å0) has a value of 5.292 × 10-11 meters. Therefore, the diameter of the atom is twice the radius, resulting in a diameter of approximately 1.0584 × 10-10 meters, which can be rounded to the order of magnitude of 10-10 m.

Answer 2

Throughout the development of particle physics, scientists have created different models to understand the atom. When we are talking about the diameter of an atom, we would refer to the Bohr radius, which is the radius from the nucleus to the orbiting electron. In this case, a hydrogen atom has one electron, and the Bohr radius in the ground state is 5.29 x 10^{-11} meters. To find the diameter, we just multiply the Bohr radius by 2. diameter = 2 x 5.29 x 10^{-11} meters diameter = 10.58 x 10^{-11} meters diameter = 1.058 x 10^{-10} meters The diameter of a hydrogen atom in ground state is: 1.058 x 10^{-10} meters