Question

Find the root that is a real number. rootindex 4 startroot 4096 endroot

Answer 1

the answer would be C.

Answer 2

Answer: 8

Explanation:
`\sqrt[4]{4096}`

We need to factor this, so

`4096|2\\2048|2\\1024|2\\512|2\\256|2\\128|2\\64|2\\32|2\\16|2\\8|2\\4|2\\2|2\\1`

`4096 = 2^(12)`

We have to remember that
`x^(n+m)=x^(n).x^(m)`

This way, we have
`\sqrt[4]{4096}=\sqrt[4]{2^(12)} = \sqrt[4]{2^(4).2^(4).2^(4)}  = 2.2.2=8`