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Factor completely 9x2 + 42x + 49. A. (3x + 7)(3x − 7) B. (9x − 7)(9x − 7) C. (3x + 7)(3x + 7) D. (9x + 7)(9x + 7)
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Factor completely 9x2 + 42x + 49.

A. (3x + 7)(3x − 7)
B. (9x − 7)(9x − 7)
C. (3x + 7)(3x + 7)
D. (9x + 7)(9x + 7)

User Marouane
by
8.0k points

1 Answer

6 votes
factor each term to see a GCF maybe

9x^2=3*3*x*x

42x=2*3*7*x

49=7*7
no gcf

ok, hum
well, we see the first term might be √9 or 3 and the last must be √49 or 7

lets try (3x+7)(3x+7)

9x^2+21x+21x+49=9x^2+42x+49
works

answer is (3x+7)(3x+7)
User Darren Ruane
by
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Factorise completely: 9x2 + 42x + 49
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