Question

33. A mass of 180kg crate is lifted by a cable with an acceleration of 2m/s.a) Draw a free body diagram (force diagram) for the crate in the space provided to the right. Be sure tolabel the force vectors b) Calculate the net force experience by the crate(Show your work including equation and substitution with units) c) Calculate the magnitude of the upward force acting on the crate. (Show your work including equation and substitution with units)

Answer 1

Answers:

b) Fnet = 360N

c) T = 2124 N

Step-by-step explanation:

Part a)

The forces acting on the crate are its weight and the tension, so the free body diagram is

Part b)

By the second law of Newton, the net force is equal to mass times the acceleration, so the net force is

Fnet = ma

Fnet = (180 kg)(2 m/s²)

Fnet = 360 N

Part c)

Taking into account the free body diagram, the net force is equal to

Fnet = T - mg

Where T is the upward force acting on the crate. Solving for T, we get:

T = Fnet + mg

Now, we can replace the values

T = 360N + (180 kg)(9.8 m/s²)

T = 360N + 1764 N

T = 2124 N

Therefore, the magnitude of the upward force is 2124 N