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B-3a=2 3B- 6a=12 solve algebraicly show steps

B-3a=2 3B- 6a=12 solve algebraicly show steps
66.9k views
2 votes
B-3a=2 3B- 6a=12 solve algebraicly show steps

User Mohit Manhas
by
8.7k points

1 Answer

2 votes
B - 3A = 2
3B - 6A = 12

(2)B - (6)A =4
3B - 6A = 12

Subtract

-B = -8
B = 8

Plugin 8 for B

8 - 3A = 2
8 = 3A + 2
6 = 3A
2 = A

(Double checking)
3(8) - 6A = 12
-6A = 12-24 = -12
- 6A = -12
Divide by -6
A= 2
It works

A = 2. B = 8. Hope this helps
User Kilsy
by
8.6k points
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