Question

1The given line passes through the points (−4, −3) and (4, 1).

What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point (−4, 3)?

y − 3 = blank (x + 4)


2Which equations represent the line that is perpendicular to the line 5x − 2y = −6 and passes through the point (5, −4)? Check all that apply.

y = –x – 2
2x + 5y = −10
2x − 5y = −10
y + 4 = –(x – 5)
y – 4 = (x + 5)

Answer 1

point slope form
y-y1=m(x-x1)
that is the equation of a line that has a slope of m and passes through (x1,y1)

ok, so find the slope
slope between(-4,-3) and (4,1)
slope=(-3-1)/(-3-4)=-4/-7=4/7
perpendiular lines have slopes that multiply to get -1
what times 4/7=-1
times both sides by 7/4
what=-7/4
the slope is -7/4
it passes through (-4,3)
y-3=-7/4(x-(-4))

`y-3=((-7)/(3))(x+4)` is the equation






2.
slope is5/2
perpendicualr means slope is -2/5
y=-2/5x+b
find b
(5,-4)
-5=(-2/5)5+b
-5=-2+b
-3=b
b=-3

y=-2/5x-3 is an equation

get into standard form
multiply both sides by 5
5y=-2x-15
add 2x
2x+5y=-15
none of them