Question

What is the value of n?



n–2=10n+42

Answer 1

To solve this equation we have to find the value of
`n`:

`n-2=10n+42`

We have to join the terms with
`n` in one side of the equation, and the other terms by the other side:

`n-10n=42+2`

Then:

`-9n=4`

-9 is multiplying
`n` and it goes to the other side dividing. Then we have the final result:

`n=-(44)/(9)`

Answer 2

n-2=10n+42
Add 2 to both sides
n=10n+44
Subtract 10n from both sides
-9n=44
Divide both sides by -9
n=(-44/9)