Question

3x^2-3x
----------- -3
x^2-9x
please give me the simplified answer + explanation

Answer 1

you want us to simplify
`(3x^2-3x)/(x^2-9x)-3`


first, factor top and bottom

`3x^2-3x=3x(x-1)`

`x^2-9x=x(x-9)`

so we have

`(3x(x-1))/(x(x-9))-3=`

`(3(x-1))/(x-9)-3`
we want to combine fractions so multiply 3 by
`(x-9)/(x-9)`

`(3(x-1))/(x-9)-(3(x-9))/(x-9)=`

`(3(x-1)-3(x-9))/(x-9)=`

`(3x-3-3x+27)/(x-9)=`

`(24)/(x-9)`


the simplified answer is
`(24)/(x-9)`