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You roll a number cube twice. What is the probability of rolling a 2 first and then rolling an odd number?

User Roam
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2 Answers

1 vote
you have a 50% to 75% chance 
User Rahul Cv
by
8.1k points
1 vote

Answer:

The probability is
(1)/(12)

Explanation:

Define the events
A and
B as the events "rolling a 2" and "rolling an odd number", respectively. Notice that the result of every rolling is independent of the previous results, so the event
A\cap B describes the phenomenon we are analazying.

On the other hand, we have that the probability of rolling a 2 is
(1)/(6) and the probability of rolling an odd number is
(1)/(2), thus


P(A\cap B) = P(A)\cdot P(B) = (1)/(6)\cdot (1)/(2) = (1)/(12).

User Kinglish
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