y= -2/5x
1) Since we have the point (5,-2) and also the slope m= -2/5. Let's find the linear coefficient, "b". By plugging into that equation: y=mx+b the following values
(x, y)
(5,-2)
m= -2/5
2) Plugging into that
y=mx+b
-2=-2/5 (5) +b
-2=-2 +b
-2+2=b
b=0
3) Finally, the equation that passes through the point (5,-2) with a slope of -2/5 is
y = -2/5x