Question

A 2.0-kg object moves in a circle of 0.50 m radius at 3.0 m/s. calculate the centripetal force.

Answer 1

mass = 2kg
radius = .5 m
v = 3m/s
centripetal force = (mv^2)/r

centripetal force = ((2)(3 ^2))/ .5
= (2 * 3 * 3) / .5
= 36

Answer 2

Centripetal force = 36 N

Step-by-step explanation:

It is given that,

Mass of an object, m = 2 kg

Radius of circle, r = 0.5 m

velocity of an object, v = 3 m/s

We have to find the centripetal force of that object. When the object moves in a circular path, the force exerted by that object is called its centripetal force. Mathematically, it is given by :

`F_c=(mv^2)/(r)`

`F_c=(2\ kg* (3\ m/s)^2)/(0.5\ m)`

`F_c=36\ N`

Hence, the centripetal force is 36 N.