Question

A particle accelerates from rest at 5.7 m/s 2 . what is its speed 7.2 s after the particle starts moving? answer in units of m/s.

Answer 1

It starts from rest meaning the initial velocity is 0

is accelerates at 5.7m/s^2 meaning a = 5.7m/s^2

t = 7.2s

vf = vi + at

vf = final velocity
vi = initial velocity
a = acceleration
t = time

we are looking for the final velocity

vf = vi + at

vf = 0 + (5.7 * 7.2)

vf = 41.04 m/s -------This is your answer