69.6k views
0 votes
An iron cube measures 3.12cm* 567cm*22.0 dm. What is the mass of this cube knowing Fe a density of 721g/mL?

1 Answer

7 votes
Calculate formula and then substitute values into the formula for mass.

V = lwh
= (3.12)(527)(220)
= 361732.8
M = Dv
= (721)(361731.8)
≈ 2608086.28 kg

I'm not exactly sure so :/
User Xcut
by
7.3k points