Density of air at 19degC = 0.001204 g/mL
assuming that density of zinc = density of air:
volume zinc = 0.587 g / (0.001204 g/mL) = 487.54 mL
then the mass zinc required is:
mass zinc = 487.54 mL * (1.85 g / 475 mL) = 1.9g
Answer:
1.9 grams
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