Question

F(x) = 4x² + 16x + 9.

Answer 1

You have the following function:

`f(x)=4x^2+16x+9`

In order to find the zeros of the previous function, use the quadratic formula:

`x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}`

In this case you have:

a = 4

b = 16

c = 9

replace the previous values into the quadratic formula:

`\begin{gathered} x=\frac{-(16)\pm\sqrt[]{(16)^2-4(4)(9)}}{2(4)} \\ x=\frac{-16\pm\sqrt[]{112}}{8} \\ x=(-16\pm10.58)/(8) \end{gathered}`

Then, you have the following values for x:

`\begin{gathered} x_1=(-16+10.58)/(8)=-(5.42)/(8)=-0.67\approx-0.7 \\ x_2=(-16-10.58)/(8)=-(26.58)/(8)=-3.32\approx-3.3 \end{gathered}`

Hence, the solution to the given function are:

x1 = -0.7

x2 = -3.3