Question

In circle with m DEF=36 and DE= 3 units find area of sector DEF. Round to the nearest hundredth.

Answer 1

2.83 units²

Step-by-step explanation:

Area of sector = θ/360 × πr²

r = radius = DE

r = 3 units

π =3.14

m∠DEF = 36°

`Area\text{ of sector =}(36)/(360)*\pi*3^2`
`\begin{gathered} \text{Area of sector =}(1)/(10)*3.14*9 \\ \text{Area of sector =}2.826 \end{gathered}`

The area of sector to the nearest hundredth, 2.83 units²