Question

What is the pressure on a fish 12.9 m under the ocean surface? (Density of ocean water = 1025 kg/m3.) atm

Answer 1

Given data:

* The depth of the fish inside the ocean is h = 12.9 m.

* The density of the ocean water is,

`\rho=1025kgm^(-3)`

Solution:

The pressure on the fish in terms of the depth of the fish is,

`P=\rho gh`

where g is the acceleration due to gravity,

Substituting the known values,

`\begin{gathered} P=1025*9.8*12.9 \\ P=129580.5\text{ Pa} \\ P=(129580.5)/(101325)\text{ atm} \\ P=1.28\text{ atm} \end{gathered}`

Thus, the pressure on a fish in the given case is 1.28 atm.