Question

One more help please. Thanks!

Answer 1

First we start out by factoring everything we can so our original problem changes to become :
`(y^2)/(y-3)` x
`((y-3)(y+2))/(y(y+1))`
Next we cancel terms so since to have a (y-3) on top and the bottom they cancel out leaving you with :
`(y^2(y+2))/(y(y+1))`
Again with a lone y on top and bottom we cancel terms leaving your answer as :
`(y(y+2))/(y+1)`

Answer 2

after factoring this gives

y ( y + 2) y^2 + 2
------------ = --------- y not equal 3 , 0 or -1
y + 1 y + 1


Its B