Register
The length of a rectangle is five times its width. if the area of the rectangle is 405 yd2 , find its perimeter.
231k views
0 votes
The length of a rectangle is five times its width. if the area of the rectangle is 405 yd2 , find its perimeter.

User Adam Houldsworth
by
6.9k points

1 Answer

3 votes
L = 5W
A = LW = 405

plug in 5W FOR L
A = LW
A = (5W)W = 405
5W^2 = 405
W^2 = 405/5
W^2 = 81
Take the squareroot
w = 9

L = 5W
We now know W = 9
L=5(9)
L =45

P=2(L+W)
P =2(45 + 9)
P =108

User Steve Atkinson
by
8.0k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

8.7m questions

11.3m answers

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
A bathtub is being filled with water. After 3 minutes 4/5 of the tub is full. Assuming the rate is constant, how much longer will it take to fill the tub?
i have a field 60m long and 110 wide going to be paved i ordered 660000000cm cubed of cement  how thick must the cement be to cover field
Link Copied!