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A man jogs at a speed of 1.6 m/s. His dog waits 1.8 s and then takes off running at a speed of 2.7 m/s to catch the man. How far will they have each traveled when the dog catches up with the man? Answer
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A man jogs at a speed of 1.6 m/s. His dog

waits 1.8 s and then takes off running at a
speed of 2.7 m/s to catch the man.
How far will they have each traveled when
the dog catches up with the man?
Answer in units of m.

User Burt Beckwith
by
8.5k points

1 Answer

2 votes
I believe it is
1.6x=2.7(x-1.8)
1.1x=2.7*1.8
x~4.4
4.4*1.6
~7.1m
User Rbyndoor
by
7.6k points
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